25x^2-104x+16=0

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Solution for 25x^2-104x+16=0 equation:



25x^2-104x+16=0
a = 25; b = -104; c = +16;
Δ = b2-4ac
Δ = -1042-4·25·16
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-96}{2*25}=\frac{8}{50} =4/25 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+96}{2*25}=\frac{200}{50} =4 $

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